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36x^2-169x+120=0
a = 36; b = -169; c = +120;
Δ = b2-4ac
Δ = -1692-4·36·120
Δ = 11281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-169)-\sqrt{11281}}{2*36}=\frac{169-\sqrt{11281}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-169)+\sqrt{11281}}{2*36}=\frac{169+\sqrt{11281}}{72} $
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